Hi,
I have idea how to change fuel usage.
Let's make 4% less for each level of drive research. Same as Ion technology give less deconstruction costs.
Formula:
FU = fu - [(D-a)*0,04 * fu]
FU - Fuel usage
fu - basic fuel usage
D - drive lvl
a - constant, different for earch drive; 5 - Combustion Drive, 4 - Impulse Drive, 3 - Hyperspace Drive -- (we can talk about value of constant 'a')
For example:
Large Cargo, fu = 50
I. Combustion Drive = 2
FU = 50 - [(2-5)*0,04*50] = 50 - [-3*0,04*50] = 50 + 6 = 56
II. Combustion Drive = 5
FU = 50 - [(5-5)*0,04*50] = 50 - [0*0,04*50] = 50 + 0 = 50
III. Combustion Drive = 20
FU = 50 - [(20 - 5)*0,04*50] = 50 - [15*0,04*50] = 50 - 30 = 20
What you say about that?
I have idea how to change fuel usage.
Let's make 4% less for each level of drive research. Same as Ion technology give less deconstruction costs.
Formula:
FU = fu - [(D-a)*0,04 * fu]
FU - Fuel usage
fu - basic fuel usage
D - drive lvl
a - constant, different for earch drive; 5 - Combustion Drive, 4 - Impulse Drive, 3 - Hyperspace Drive -- (we can talk about value of constant 'a')
For example:
Large Cargo, fu = 50
I. Combustion Drive = 2
FU = 50 - [(2-5)*0,04*50] = 50 - [-3*0,04*50] = 50 + 6 = 56
II. Combustion Drive = 5
FU = 50 - [(5-5)*0,04*50] = 50 - [0*0,04*50] = 50 + 0 = 50
III. Combustion Drive = 20
FU = 50 - [(20 - 5)*0,04*50] = 50 - [15*0,04*50] = 50 - 30 = 20
What you say about that?
The post was edited 2 times, last by chemikos ().